5x+6y=30
4x+6y=-28
I am supposed to find where they intersect, I found the x (x=19) but I cant figure out how to find the y.
clearly you did not get x right.
The two equations are the same except that the 1st has one more x in it. So, if you subtract #2 from #1, you end up with
x = 58
Using that in either equation to find y, you have
5*58 + 6y = 30
6y = -260
y = -130/3
4*58 + 6y = -28
6y = -260
y = -130/3
Yet, somehow I suspect a typo.
Oh 🤦♀️ Thank you i see it now. I mixed up my x with another problem
To find the value of y, you can use the method of elimination or substitution. Let's use the method of elimination for this problem.
Given the system of equations:
1) 5x + 6y = 30
2) 4x + 6y = -28
To eliminate the term "6y" in both equations, we'll multiply equation 1 by 4 and equation 2 by 5:
4 * (5x + 6y) = 4 * 30
5 * (4x + 6y) = 5 * (-28)
Simplifying these equations, we get:
20x + 24y = 120
20x + 30y = -140
Now, subtract equation 2 from equation 1:
(20x + 24y) - (20x + 30y) = 120 - (-140)
This simplifies to:
-6y = 260
Divide both sides of the equation by -6:
y = 260 / -6
Calculating this, we find:
y = -43.3333 (rounded to 4 decimal places)
So, the coordinates of the point where the two lines intersect are (x = 19, y = -43.3333).
Please note that if you found the value of x to be 19, it might not be correct since I don't have your step-by-step calculations. However, following the above method will help you find the correct solution.