Find the 68th term of the arithmetic sequence -19, -33, -47, ...
https://www.mathsisfun.com/algebra/sequences-sums-arithmetic.html
https://en.wikipedia.org/wiki/Arithmetic_progression
NOTE: x = (n-1)*d.
x is the final answer.
n = number of terms, n this case n = 68
d = difference between terms.
oops. I made a typo and left out a term in my example. The url I gave gives the correct formula.
To find the 68th term of the arithmetic sequence -19, -33, -47, ..., you will need to use the formula for the nth term of an arithmetic sequence.
The formula for the nth term of an arithmetic sequence is given by:
an = a1 + (n - 1) * d
Where:
an represents the nth term in the sequence,
a1 represents the first term in the sequence, and
d represents the common difference between each term.
In this case, the first term (a1) is -19, and the common difference (d) is -33 - (-19) = -14.
Now you can substitute these values into the formula to find the 68th term:
a68 = -19 + (68 - 1) * (-14)
Simplifying the equation:
a68 = -19 + 67 * (-14)
a68 = -19 - 938
a68 = -957
Therefore, the 68th term of the arithmetic sequence -19, -33, -47, ... is -957.