Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Mathematics
If the hypotenuse is 41 inches and one of the legs are 40 inches how long is the other??
1 answer
40^2 + x^2 = 41^2
x^2 = 1681 - 1600
x^2 = 81
x = 9
You can
ask a new question
or
answer this question
.
Related Questions
Quilt squares are cut on the diagonal to form triangular quilt pieces. The hypotenuse of the resulting triangles is 18 inches
A semicircle is constructed along each side of a right triangle with legs 6 inches and 8 inches. The semicircle placed along the
If the legs of a right triangle have lengths of 6 inches and 8 inches, what is the length of the hypotenuse in inches?
A.11 B.13
Kym’s sawhorse is 39 inches tall, 27 inches long, and 19 inches wide. Its diagonal measurement, or the hypotenuse, is 40.14
A picture frame is 12 inches long and 9 inches wide. In inches, what is the diagonal length of the picture frame?
A)12 inches
The hypotenuse (side C) of a triangle is 13 inches long. Which of the following pairs of measurements could be correct for the
Kym’s sawhorse is 39 inches tall, 27 inches long, and 19 inches wide. Its diagonal measurement, or the hypotenuse, is 40.14
Stacey needs to buy some cardboard to build a box 10 inches long, 9 inches wide, and 7 inches high. If she purchases 500 square
Kym’s sawhorse is 39 inches tall 27 inches long and 19 inches wide it’s diagonal measurement of the hypotenuse is 40.14
The two legs of a right triangle are 10 inches and 7 inches. What is the length of the hypotenuse to the nearest inch?
A.17 B.12