how would you prepare 500 mL of a 1.5 M NaOH solution, starting with a 5.0M NaOH solution?
This is a dilution so use the dilution formula of
mL1 x M1 = mL2 x M2
500 x 1.5 = ? x 5.0
Solve for ?, pipet that number of mL into a 500 mL volumetric flask, add distilled water to the mark of the flask, mix thoroughly, stopper, label.
To prepare 500 mL of a 1.5 M NaOH solution starting with a 5.0 M NaOH solution, you will need to dilute the 5.0 M solution with water. Here's how you can do it:
Step 1: Determine the volume of the concentrated 5.0 M NaOH solution you will need. The formula to calculate this is:
Volume1 * Concentration1 = Volume2 * Concentration2
Let's denote:
Volume1 = volume of concentrated solution
Concentration1 = concentration of concentrated solution
Volume2 = volume of diluted solution (500 mL)
Concentration2 = concentration of diluted solution (1.5 M)
Using the formula, we have:
Volume1 * 5.0 M = 500 mL * 1.5 M
Solving for Volume1:
Volume1 = (500 mL * 1.5 M) / 5.0 M
Volume1 = 150 mL
So, you will need to measure 150 mL of the 5.0 M NaOH solution.
Step 2: Transfer the 150 mL of the 5.0 M NaOH solution to a container.
Step 3: Add distilled water to the container to make up the desired total volume of 500 mL. Since you already have 150 mL of the concentrated solution, you will need to add:
500 mL - 150 mL = 350 mL of distilled water
Step 4: Thoroughly mix the contents of the container to ensure uniform distribution.
By following these steps, you will have successfully prepared 500 mL of a 1.5 M NaOH solution starting with a 5.0 M NaOH solution.