Which equation shows p(x)=x6−1 factored completely over the integers? (Hint: You will need to use more than one method to complete this problem.)

p(x)=(x3+1)(x3−1)
p(x)=(x2−1)(x4+x2+1)
p(x)=(x−1)(x2+x+1)(x+1)(x2−x+1)
p(x)=(x−1)(x+1)(x4+x2+1)

p(x)=(x3+1)(x3−1)?

For the people in the future, I just took the test and Ace's answer is right.