A sleigh currently runs at 203mph, but he needs it to reach 400mph with all the packages he has to deliver.
If Goldberg is delivering presents at an altitude of 5,813.6ft, with the same drag and weight of a 2019 Challenger SRT® Hellcat Redeye, how much HP would he need to reach 400 mph?
TIPS : 100% driveline efficiency
P (air density) at 5813.6 ft = .0019 slug/ft^3
A (Area of Challenger front end) = 26.72 ft^2
C(d) (Coefficient of drag) = .398
Goldberg's sleigh required speed, 400 MPH = 587 ft/sec
F(drag) = 1/2 p x v^2 x C(d)A
P = F(drag) x V
Convert to Horsepower = P ( 1HP/550 ft lbf/sec)
I don't know if that is correct. I was more curious than testing anyone. I saw the question. I have a Challenger (not the Hellcat) and the whole idea seems nuts but I wanted to know. I saw another answer of 5813. Both numbers seem pretty far fetched to me. I'm not into muscle cars for the speed. Just love the designs.
Well I calculate for my self but I don't sure???? They give me a formula Fdrad= 1/2PxV^2xCdxA and P=FdragxV for converting that in HP = Px(1hp/550 ft lbf/sec) ok. Fdrag=1/2 (0.0019)×(587)^2×0.398×26.72
Fdrag= 3,481.12272 slugft/sec^2
P=Fdrag×V
P=2,043,418.0363
Convert to HP = P/550
3715.3073 HP. Is that correct?????
If that is the answer I hop help some body!!!!!!
Well I calculate for my self but I don't sure???? They give me a formula Fdrad= 1/2PxV^2xCdxA and P=FdragxV for converting that in HP = Px(1hp/550 ft lbf/sec) ok. Fdrag=1/2 (0.0019)×(587)^2×0.398×26.72
Fdrag= 3,481.12272 slugft/sec^2
P=Fdrag×V
P=2,043,418.0363
Convert to HP = P/550
3715.3073 HP. Is that correct?????
To calculate the horsepower (HP) required to reach a speed of 400 mph with Goldberg's sleigh, we need to consider the drag force acting on the sleigh.
First, let's calculate the drag force (F_drag) using the given information:
P (air density) at 5813.6 ft = 0.0019 slug/ft^3
A (Area of Challenger front end) = 26.72 ft^2
C(d) (Coefficient of drag) = 0.398
Goldberg's sleigh required speed, 400 mph = 587 ft/sec
The drag force formula is F_drag = (1/2) × P × v^2 × C(d) × A, where P is the air density, v is the velocity, C(d) is the drag coefficient, and A is the front end area.
Plugging in the values, we get:
F_drag = (1/2) × 0.0019 × (587)^2 × 0.398 × 26.72
Next, we can calculate power (P) using the formula:
P = F_drag × v
Substituting the values, we have:
P = (F_drag) × (587)
Finally, to convert power to horsepower, we can use the conversion factor:
1 horsepower = 550 ft lbf/sec
So, the final formula to calculate horsepower is:
Horsepower = P / 550
Substituting the values, we can now calculate the horsepower required for Goldberg's sleigh to reach 400 mph.