C = 4.6 A x 85 min x (60 seconds/min) = ? = estimated 23,000 but you need to redo all of the calculations.
107.9 grams Ag will be deposited by 96,485 coulombs so
107.9 x 23,000/96,485 = ? will be deposited with 23,000 C.
Post your work if you get stuck.
