how many cm³ of hydrogen chloride gas at stp would be required to precipitate all the silver ions from 32cm³ of 0.08molar silver nitrate solution?
Ag^+ + Cl^- --> AgCl
millimols Ag^+ = mL x M = 32 x 0.08 = 2.56
So you will need 2.56 millimols HCl or 0.00256 mols HCl
1 mol HCl @ STP occupies 22.4 L so 0.00256 mols HCl will occupy ? L. Convert this to mL or cc.