How many gram of hydrogen chloride acid containing 10% by mass of hydrogen chloride acid would be required to dissolve 13g of zinc
making ZnCl2
2HCl + Zn ---> ZnCl2 + H2
so I need 2 mols of HCl for every one of Zn
mol mass of Zn = about 65
13/65 = 0.2 Mol of Zn
so need 0.4 mol of HCl
How many grams of HCl is that ?
mol of HCl = 1 + 35.5 = 36.5 grams/mol
.4 * 36.5 = 14.6 grams of HCl
14.6 = 0.10 * mass of fluid in bottle of HCl
so 146 grams fluid in bottle needed
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 13 g/atomic mass = estimated 0.2 but you need a better number on ALL of these calculations.
0.2 mols Zn x (2 mols HCl/1 mol Zn) = estd 0.4 mols HCl.
g HCl = mols HCl x molar mass HCl = estd 15 grams if it were 100%. It is only 10%; therefore, about 15/0.10 = about 150 grams.
Post your work if you get stuck.
I don't understand the solving?
Ah, the age-old question of chemistry and zinc's affinity for humor. Well, to dissolve 13g of zinc using hydrochloric acid, we need to do a little math, but fear not, my friend, I'm here to make it fun!
Now, if we have hydrochloric acid that's 10% hydrogen chloride, it means that for every 100g of the acid, we have 10g of hydrogen chloride. So, let's calculate the amount of hydrochloric acid we need!
To dissolve 13g of zinc, we'll need an equal amount of hydrogen chloride. Since hydrogen chloride makes up 10% of hydrochloric acid, we divide 13g by 10% (or 0.10) to find out how much hydrochloric acid we need.
13g ÷ 0.10 = 130g
Voilà! We need 130 grams of hydrochloric acid containing 10% hydrogen chloride to dissolve that stubborn 13g of zinc. Now, go out there and conquer that chemical reaction with a smile!
To determine the amount of hydrogen chloride acid (HCl) required to dissolve a given mass of zinc (Zn), we need to use stoichiometry and the molar mass of hydrogen chloride acid.
First, calculate the molar mass of HCl:
H = 1 gram/mol
Cl = 35.5 gram/mol
Molar mass of HCl = 1 + 35.5 = 36.5 gram/mol
Next, calculate the amount of HCl required to dissolve the given mass of zinc using the balanced equation:
Zn + 2HCl -> ZnCl2 + H2
The molar ratio between Zn and HCl is 1:2, meaning that for every mole of Zn, we need two moles of HCl.
Now, we can proceed with the calculations:
1. Convert the mass of zinc to moles:
13 grams of Zn x (1 mol/65.38 g) ≈ 0.199 mol of Zn
2. Since the molar ratio of Zn to HCl is 1:2, we need twice as many moles of HCl as Zn:
0.199 mol of Zn x 2 mol of HCl/1 mol of Zn = 0.398 mol of HCl
Finally, to determine the mass of HCl required, multiply the moles of HCl by the molar mass of HCl:
0.398 mol of HCl x 36.5 g/mol = 14.527 grams of HCl
Therefore, approximately 14.527 grams of hydrogen chloride acid containing 10% HCl by mass would be required to dissolve 13 grams of zinc.