CN−(aq)+H3O+(aq)⟵−→−H2O(l)+HCN(aq)
CN−(aq)+H3O+(aq)⟵−→−H2O(l)+HCN(aq)
Interesting but I don't think so. I think you meant to write this.
CN−(aq) + H2O(aq)⟵−→OH^-(aq) + HCN(aq)
If you actually meant to write what you had this is more like it.
CN−(aq) + H3O+(aq)⟵−→H2O(l) + HCN(g)
The given equation represents a chemical reaction that occurs in an aqueous solution. It shows the reaction between the cyanide ion (CN-) and the hydronium ion (H3O+) to produce water (H2O) and hydrogen cyanide (HCN) in both aqueous and liquid forms.
To understand the reaction, it is important to know that cyanide ion (CN-) is a strong base and hydronium ion (H3O+) is an acid. In the reaction, the cyanide ion acts as a base by accepting a proton (H+) from the hydronium ion, which acts as an acid. This proton transfer forms water and hydrogen cyanide.
If you want to predict whether this reaction occurs, you can consider the relative strengths of the acids and bases involved. In this case, since cyanide ion is a stronger base compared to hydronium ion, the reaction is favorable and will occur.
The arrow (⟵−→) between the reactants and products indicates that the reaction is reversible, meaning both forward and reverse reactions can occur simultaneously.