How do you find the skeleton equation for

lithium chromate(aq)+ barium chloride (aq) ==> lithium chloride (aq)+ barium chromates(s)

nickel(II) oxide(s) +oxygen(g)==> nickel(II) oxides(S)+dichlorine pentoxide(g)

lithium chromate(aq)+ barium chloride (aq) ==> lithium chloride (aq)+ barium chromates(s)

Li2CrO4(aq) + BaCl2(aq) ==> LiCl(aq) + BaCrO4(s)

nickel(II) oxide(s) +oxygen(g)==> nickel(II) oxides(S)+dichlorine pentoxide(g)
NOTE: You haven't copied the second equation correctly. There is no way you can get Cl2O5 when you don't have chlorine or a chlorine product anywhere in the equation

To find the skeleton equation for these chemical reactions, we need to follow a few steps:

For the first equation:
1. Write down the balanced formula for each compound involved:
- Lithium chromate: Li2CrO4 (aq)
- Barium chloride: BaCl2 (aq)
- Lithium chloride: LiCl (aq)
- Barium chromate: BaCrO4 (s)

2. Separate the reactants(left side) and products(right side) using the arrow (==>) sign:
- Lithium chromate(aq) + Barium chloride(aq) ==> Lithium chloride(aq) + Barium chromate(s)

3. Balance the equation by adding coefficients in front of the compounds to ensure that the same number of atoms of each element are present on both sides of the equation:
- Li2CrO4 (aq) + BaCl2 (aq) ==> 2LiCl (aq) + BaCrO4 (s)

So, the skeleton equation for the first reaction is:
Li2CrO4 (aq) + BaCl2 (aq) ==> 2LiCl (aq) + BaCrO4 (s)

For the second equation:
1. Write down the balanced formula for each compound involved:
- Nickel(II) oxide: NiO (s)
- Oxygen: O2 (g)
- Nickel(II) oxide: NiO (s)
- Dichlorine pentoxide: Cl2O5 (g)

2. Separate the reactants and products using the arrow (==>) sign:
- Nickel(II) oxide(s) + Oxygen(g) ==> Nickel(II) oxide(s) + Dichlorine pentoxide(g)

3. Balance the equation by adding coefficients in front of the compounds to ensure that the same number of atoms of each element are present on both sides of the equation:
- NiO (s) + O2 (g) ==> 2NiO (s) + Cl2O5 (g)

So, the skeleton equation for the second reaction is:
NiO (s) + O2 (g) ==> 2NiO (s) + Cl2O5 (g)

To find the skeleton equations for these chemical reactions, we need to follow a few steps:

1. Identify the reactants and products: Determine the elements and compounds involved in the reaction and write them down.

For the first equation:
Reactants: lithium chromate(aq) and barium chloride(aq)
Products: lithium chloride(aq) and barium chromate(s)

For the second equation:
Reactants: nickel(II) oxide(s) and oxygen(g)
Products: nickel(II) oxide(s) and dichlorine pentoxide(g)

2. Write the skeleton equation: Start by writing the reactants on the left side of the arrow and the products on the right side of the arrow. Use their correct chemical formulas.

First equation:
lithium chromate(aq) + barium chloride(aq) → lithium chloride(aq) + barium chromate(s)

Second equation:
nickel(II) oxide(s) + oxygen(g) → nickel(II) oxide(s) + dichlorine pentoxide(g)

Make sure to double-check that the chemical formulas are balanced. In a skeleton equation, we don't include coefficients yet.

3. Balance the equation: After writing the skeleton equations, we need to balance them by adding coefficients to ensure the same number of atoms on both sides of the equation.

For example, in the first equation, we have two chlorides on the reactant side (from barium chloride) and one chloride on the product side (from lithium chloride). To balance the equation, we can add a coefficient of 2 in front of lithium chloride:

lithium chromate(aq) + barium chloride(aq) → 2 lithium chloride(aq) + barium chromate(s)

Similarly, you need to balance the second equation by adding coefficients.

nickel(II) oxide(s) + oxygen(g) → nickel(II) oxide(s) + dichlorine pentoxide(g)

Since nickel(II) oxide already appears on both sides of the equation, it is already balanced. However, dichlorine pentoxide needs to be balanced. We can add a coefficient of 5 in front of dichlorine pentoxide to balance the number of chlorine atoms:

nickel(II) oxide(s) + oxygen(g) → nickel(II) oxide(s) + 5 dichlorine pentoxide(g)

That's it! You have now found the skeleton equations for the given chemical reactions.