what type of reaction is for Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2
is it decomposition
or synthesis
or double replacement
DOUBLE REPLACEMENT (OR DOUBLE DISPLACEMENT)
The reaction Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 is a double replacement reaction. In a double replacement reaction, the positive ions in the reactants switch places with each other to form new compounds. In this case, the lead (Pb) cation in Pb(NO3)2 and the copper (Cu) cation in CuSO4 switch places, resulting in the formation of PbSO4 and Cu(NO3)2.
The reaction you provided, Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2, is a double replacement reaction. In a double replacement reaction, the cations (positively charged ions) and anions (negatively charged ions) of two different compounds switch places to form two new compounds.
In this case, the lead (Pb^2+) cation from lead(II) nitrate (Pb(NO3)2) combines with the sulfate (SO4^2-) anion from copper(II) sulfate (CuSO4) to form lead(II) sulfate (PbSO4). Additionally, the copper (Cu^2+) cation from copper(II) sulfate combines with the nitrate (NO3^-) anion from lead(II) nitrate to form copper(II) nitrate (Cu(NO3)2).
So, the reaction you provided is a double replacement reaction where the cations and anions of the reactants exchange places to form new compounds.
Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2
Note that it is
AB2 + CD ==> AD + CB2