Mia has a bag of candy. She has 6 kitkats, 5 twit, and 2 crush bars. What is the probability that Mia will NOT choose a twin if she randomly puts her hand into the bag and pulls out a candy bar? Show all your work.
A. 5/13
B. 2/13
C. 8/13
D. 7/13
I'll be glad to check your answer.
To figure out probabilities, first thing you do is add up the total number of items. 6+5+2=13
The answer to that is your denominator.
From now on I'll be refering to the Twix as 'x'. With problems like this (finding the probability of not picking something) the formula is to subtract x from the denominator.
13-5=8
The answer to this is your numerator. So your answer is 8/13.
This is basically how to do it, so put into your own words how you would do it. Hope this helps :3
To find the probability that Mia will NOT choose a twin, we need to first calculate the total number of candies and then determine the number of twins in the bag.
The total number of candies Mia has is 6 kitkats + 5 twix + 2 crush bars = 13 candies.
The number of twins in the bag is 5.
The probability of not choosing a twin is calculated by subtracting the number of twins from the total number of candies and then dividing by the total number of candies.
Probability of NOT choosing a twin = (Total candies - Number of twins) / Total candies = (13 - 5) / 13 = 8 / 13
Therefore, the answer is option C. 8/13