Adaobi walks 2km due West and then 2km due south represent the diagram and calculate the displacement of Adaobi
I can't draw a diagram, howver displacement is 2kmW+2kmS, or 2*sqrt2 @225 deg (from due N).
Disp. = -2 - 2i = 2.83km[45o] S. of W. = 2.83km[225o] CCW.
To represent Adaobi's movements on a diagram, start by drawing a horizontal line to represent the motion of her first movement, which is 2 km due West. Label this line as "2 km West." Then, from the end of this line, draw a vertical line downwards to represent Adaobi's second movement, which is 2 km due south. Label this line as "2 km South." The lines should meet at a point, indicating Adaobi's final position.
To calculate Adaobi's displacement, we can use the Pythagorean theorem. The displacement is the shortest distance from the starting point to the end point. In this case, since Adaobi walked 2 km due West and then 2 km due South, the displacement is the length of the hypotenuse of the right-angled triangle formed by these two sides.
Using the Pythagorean theorem, we can calculate the displacement as follows:
Displacement = √(2^2 + 2^2)
= √(4 + 4)
= √8
≈ 2.83 km
Therefore, the displacement of Adaobi is approximately 2.83 km.