A ball is dropped from rest from a height
of h. It takes 1 second for the ball to drop
from h/2 to the ground. From what
height was the ball dropped?
timetofall=1=sqrt((h/2)/4.9 from h/2=1/2 g t^2
h/2= 4.9^2 * 1
h=2*4.9^2 check that.
To determine the height from which the ball was dropped, we can use the equation of motion for freely falling objects. The equation is:
h = 1/2 * g * t^2
Where:
h is the height
g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth)
t is the time taken for the ball to fall
In this case, we know that the ball takes 1 second (t = 1) to fall from h/2 to the ground. Let's plug in the values into the equation and solve for h:
h = 1/2 * 9.8 * 1^2
h = 4.9 meters
Therefore, the ball must have been dropped from a height of 4.9 meters in order for it to take 1 second to fall from h/2 to the ground.