A tug tows a small boat with a rope inclined upward at 30 degrees to the horizontal. The tension in the string is 2000N.What is the forces tending to raise the boat out of water.
what is 2000*cos30?
I think I like sin30
Just for future reference, consider the extreme cases.
0° means no upward pull at all. sin0 = 0
90° means a pull straight up. sin90 = 1, the full amount pulls up
To find the forces tending to raise the boat out of water, we first need to break down the tension force into its horizontal and vertical components.
Given:
Tension (T) = 2000N
Angle of inclination (θ) = 30 degrees
1. Calculate the vertical component of the tension force:
Vertical Component (T_v) = T * sin(θ)
= 2000N * sin(30°)
2. Calculate the horizontal component of the tension force:
Horizontal Component (T_h) = T * cos(θ)
= 2000N * cos(30°)
Now, let's solve for the vertical component of the tension force.
1. Calculate the vertical component:
T_v = 2000N * sin(30°)
T_v ≈ 1000N
Therefore, the vertical component of the tension force is approximately 1000N.
The vertical component of the tension force is the force that tends to raise the boat out of the water. Hence, the force tending to raise the boat out of the water is approximately 1000 Newtons.