A pointer attached to a sperical spring pointed to the 25.00mm mark on a scale when the spring was carrying a load of 0.1000N and 28.00mm when it was carrying a load of 0.15N to what graduation on the scale would it point when the spring was carrying o.175N
sperical spring???
reading=k*x + b
25=k*.100+b and
28=k*.150 + b
so solve for k and b
a. subtrac1 1 from 2.
3=.05k k= 60
now go back and solve for b.
then calculate the answer
To find the graduation on the scale to which the pointer would point when the spring is carrying a load of 0.175N, we can use the concept of Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.
In this case, we can assume that the spring follows Hooke's Law, where the force (F) is proportional to the displacement (x) of the spring. Hence, we have the equation:
F = kx
Where:
F = Force applied to the spring (in Newtons)
k = Spring constant (in N/m)
x = Displacement of the spring (in meters)
To find the spring constant (k) using the given information, we can use the first data point:
0.1000N = k * 0.025m
From this, we can solve for k:
k = 0.1000N / 0.025m
k = 4 N/m
Now that we have the spring constant, we can find the displacement (x) when the spring is carrying a load of 0.175N. Rearranging Hooke's Law, we have:
x = F / k
Substituting the values:
x = 0.175N / 4 N/m
x = 0.04375 m
Therefore, when the spring is carrying a load of 0.175N, the pointer attached to the spherical spring would point to the 43.75mm mark on the scale.