How many milliliter of 4m of naoH must be added to 100ml of 0.2000m H2S04 solution to completely neutralise the acid .the balance chemical equation is H2S04+NaoH........Na2S04+2H20?
Balanced? Count Sodium atoms and Hydrogen atoms.
No, it isn't balanced.
Also note that m stands for MOLALITY and M stands for MOLARITY. I'm sure you mean M but that isn't what you typed.
To find the volume of 4M NaOH required to completely neutralize 100mL of 0.2000M H2SO4, we can use the concept of stoichiometry.
Let's first understand the balanced chemical equation provided:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
From the balanced equation, we can see that one mole of H2SO4 reacts with two moles of NaOH.
To determine the number of moles of H2SO4 in the 100mL solution, we can use the formula:
moles = concentration × volume / 1000
moles of H2SO4 = 0.2000M × 100mL / 1000 = 0.020 moles
According to the stoichiometry of the balanced equation, the ratio between moles of H2SO4 and moles of NaOH is 1:2. Therefore, we need twice as many moles of NaOH as moles of H2SO4.
moles of NaOH = 2 × moles of H2SO4 = 2 × 0.020 = 0.040 moles
Now, we can calculate the volume of 4M NaOH required to obtain 0.040 moles using the same formula:
volume = moles / concentration
volume of NaOH = 0.040 moles / 4M = 0.010 L = 10 mL
Therefore, you would need to add 10 mL of 4M NaOH to completely neutralize the 100 mL of 0.2000M H2SO4 solution.