A solution of 0.170 M NaOH is used to titrate 24.0 mL of a solution of H2S04:
H2S04(aq) + 2NaOH(ag) → 2H20(1) + Na2SO4 (aq)
If 39.8 mL of the NaOH solution is required to reach the endpoint, what is the molarity of the H2SO4 solution?
Express your answer with the appropriate units.
From the balanced equation, we can see that the mole ratio between NaOH and H2SO4 is 2:1.
We are given the volume of NaOH solution required to reach the endpoint, which is 39.8 mL.
Using the equation M1V1 = M2V2, where M1 is the molarity of the NaOH solution, V1 is the volume of NaOH solution used, M2 is the molarity of the H2SO4 solution, and V2 is the volume of the H2SO4 solution that reacts with the NaOH solution, we can substitute the given values into the equation:
(0.170 M)(39.8 mL) = M2 (24.0 mL)
Simplifying this equation, we get:
6.766 = M2 (24.0 mL)
Dividing both sides of the equation by 24.0 mL, we find:
M2 = 6.766 / 24.0
M2 ≈ 0.2824 M
Therefore, the molarity of the H2SO4 solution is approximately 0.2824 M.
To find the molarity of the H2SO4 solution, we can use the concept of stoichiometry.
Step 1: Determine the balanced equation for the reaction:
H2SO4(aq) + 2NaOH(ag) → 2H2O(l) + Na2SO4(aq)
Step 2: Use the balanced equation to determine the mole ratio between H2SO4 and NaOH. From the equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.
Step 3: Calculate the number of moles of NaOH used in the titration.
Number of moles of NaOH = Molarity × Volume
= 0.170 M × 39.8 mL
= 0.006766 mol
Step 4: Use the mole ratio from step 2 to determine the number of moles of H2SO4.
Number of moles of H2SO4 = (Number of moles of NaOH) / 2
= 0.006766 mol / 2
= 0.003383 mol
Step 5: Calculate the molarity of the H2SO4 solution.
Molarity of H2SO4 = Number of moles / Volume
= 0.003383 mol / 24.0 mL
= 0.141 M
Therefore, the molarity of the H2SO4 solution is 0.141 M.
To find the molarity of the H2SO4 solution, we need to use the concept of stoichiometry and the relationship between the moles of the reactants and the volume of the solution used.
First, let's find the number of moles of NaOH used in the titration:
Molarity of NaOH solution = 0.170 M
Volume of NaOH solution used = 39.8 mL = 0.0398 L
Using the equation balanced equation, we can see that the stoichiometric ratio between NaOH and H2SO4 is 2:1. Therefore, the number of moles of H2SO4 will be half the number of moles of NaOH used.
Number of moles of NaOH = Molarity × Volume = 0.170 M × 0.0398 L = 0.006766 mol
Number of moles of H2SO4 = 0.006766 mol / 2 = 0.003383 mol
Now, let's find the molarity of the H2SO4 solution:
Volume of H2SO4 solution used = 24.0 mL = 0.0240 L
Molarity of H2SO4 = Number of moles / Volume = 0.003383 mol / 0.0240 L = 0.14096 M
So, the molarity of the H2SO4 solution is 0.14096 M.
Please note that it's important to show all the steps in your calculations to ensure accuracy and understanding of the solution.