Question

h(x) = 3(2)^x, Section A is from x = 1 to x = 2 and Section B is from x = 3 to x = 4.

Part 1: Find the average rate of change of each section.

Part 2: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other.

Rather than just submitting the answer can you show me how you got there too, so I can fully understand? Thanks.

Answer 1

for each interval [a,b] the average rate of change is just the slope of the line joining the two points of the graph at the endpoints of the interval. That is

(h(b)-h(a))/(b-a)

to compare, just divide. Why greater? The function grows faster, duh.