Ash sold 325 tickets to a football playoff game. Adult tickets were $5 each and student tickets were $2 each. If ASB made $995, how many of each ticket were sold?
Yes, your equations are correct:
x+y=325
5x+2y=$995
One way you can continue is you can solve for y in the first equation:
x+y=325
y = 325 - x
Then, you can substitute y in the second equation:
5x+2y=$995
5x+2(325 - x)=$995
Can you take it from here?
You're welcome!
I believe It’s one of those x+y=325 and 5x+2y=$995. However it’s been a while since I’ve done one of these and I don’t know how to solve it
Ohh okay. Yeah I got it. Thanks you
To solve this problem, we can set up a system of equations.
Let's assume the number of adult tickets sold is "x" and the number of student tickets sold is "y".
From the problem, we know that the total number of tickets sold is 325:
x + y = 325 --- Equation (1)
We also know that the total revenue from selling adult tickets is $5 times the number of adult tickets sold:
5x
Similarly, the total revenue from selling student tickets is $2 times the number of student tickets sold:
2y
The total revenue from both types of tickets is given as $995:
5x + 2y = 995 --- Equation (2)
Now, we can solve these equations simultaneously to find the values of "x" and "y".
Multiplying Equation (1) by 2, we get:
2x + 2y = 650
Subtracting Equation (2) from this modified Equation (1), we get:
(2x + 2y) - (5x + 2y) = 650 - 995
-3x = -345
Dividing both sides of the equation by -3, we find:
x = 115
Now, substitute the value of x back into Equation (1):
115 + y = 325
y = 325 - 115
y = 210
Therefore, Ash sold 115 adult tickets and 210 student tickets.