A light bulb with a resistance of 3.0 ohms has a voltage difference of 6.0 V across its leads. What is the current through the bulb?
what is I=E/R=6/3 amps?
2.0 AMPS!
To find the current through the bulb, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage difference (V) across its terminals divided by the resistance (R) of the resistor.
So, we can use the formula:
I = V / R
Plugging in the given values:
I = 6.0 V / 3.0 ohms
Simplifying the equation:
I = 2.0 Amperes
Therefore, the current flowing through the bulb is 2.0 Amperes.
To find the current through the bulb, you can use Ohm's Law, which states that the current (I) flowing through a device is equal to the voltage (V) across the device divided by its resistance (R). Mathematically, it can be expressed as:
I = V / R
Given that the resistance (R) of the light bulb is 3.0 ohms and the voltage difference (V) across its leads is 6.0 V, you can plug these values into the equation to compute the current (I):
I = 6.0 V / 3.0 ohms
= 2.0 Amps
Therefore, the current through the light bulb is 2.0 Amps.