a force of 2N stretches an elastic material by 30mm. What additional force will stretch the material by 35mm assuming the elastic limit is not exceeded
asked on
35/30 * 2N = 14/6 = 2.33 N. = Force required to stretch it 35 mm.
2.33 - 2 =__ N. = Additional force.
To determine the additional force required to stretch the elastic material by 35mm, we can use Hooke's Law. Hooke's Law states that the force required to stretch or compress an elastic material is directly proportional to the displacement. Mathematically, it can be written as:
F = k * x
Where:
F is the force applied
k is the spring constant or stiffness of the material
x is the displacement or change in length
In this case, we are given that a force of 2N stretches the material by 30mm. Let's assume the spring constant for this material is k.
So, according to Hooke's Law, we can write the following equation:
2N = k * 30mm
To find the spring constant (k), we rearrange the equation:
k = 2N / 30mm
Now, we can use this value of k to find the additional force required to stretch the material by 35mm.
Let's substitute the given displacement (x = 35mm) and the calculated value of k into Hooke's Law:
F = k * x
F = (2N / 30mm) * 35mm
Simplifying the equation:
F = (2N * 35mm) / 30mm
F = 70N / 30
F ≈ 2.33N
Therefore, an additional force of approximately 2.33N is required to stretch the material by 35mm, assuming the elastic limit is not exceeded.
2/30=(2+Additional)/35
wondering if the 35 incudes the initial stretch...poorly worded.