A 8kg mass rests on an inclined plane. If the limiting frictional force of 50N and g=10m/s2, then the angle of inclination of the plane is?
M*g = 8 * 10 = 80 N.
Fp = 80*sin A = Force parallel with the incline.
Fp - Fs = M*a,
80*sinA - 50 = 8 * 0,
80*sinA - 50 = 0,
A = 38.7 deg.
Fs = Force of static friction.
To find the angle of inclination of the plane, we need to use the concept of equilibrium and the relationship between the force of friction and the normal force.
The force of gravity acting on the mass can be calculated using the formula:
Force of gravity = mass * acceleration due to gravity (g)
Force of gravity = 8 kg * 10 m/s^2
Force of gravity = 80 N
At equilibrium, the component of the force of gravity parallel to the incline is balanced by the force of friction. This component of the force of gravity can be calculated using the formula:
Force parallel to the incline = Force of gravity * sin(angle of inclination)
80 N * sin(angle) = 50 N
To find the angle of inclination, we can rearrange the equation:
sin(angle) = 50 N / 80 N
sin(angle) = 0.625
Now, we need to find the inverse sine (also known as arcsine) of 0.625 to find the angle:
angle = arcsin(0.625)
angle ≈ 38.7 degrees
Therefore, the angle of inclination of the plane is approximately 38.7 degrees.