6.54 of zink must react with excess dilute hydrochloride acid calculate the volume of the hydrogen at s.t.p zn+21+cl= zncl+ h(g) [zn=65.4]
how many moles produced?
22.4 L/mole at STP
To calculate the volume of hydrogen gas produced, we need to use the ideal gas law equation and stoichiometry.
The balanced chemical equation for the reaction is:
Zn + 2HCl → ZnCl2 + H2
From the equation, it is clear that the mole ratio between Zn and H2 is 1:1.
Given that 6.54 g of Zn is reacted, we need to convert this amount to moles. The molar mass of Zn is 65.4 g/mol (as given), so the number of moles of Zn can be calculated as follows:
Number of moles of Zn = Mass of Zn / Molar mass of Zn
= 6.54 g / 65.4 g/mol
= 0.1 mol
Since the stoichiometry of the reaction is 1:1 between Zn and H2, the number of moles of H2 produced will also be equal to 0.1 mol.
According to the ideal gas law equation:
PV = nRT
At standard temperature and pressure (STP), the values are:
P = 1 atm (pressure)
V = ? (volume)
n = 0.1 mol (number of moles of H2)
R = 0.0821 L·atm/(mol·K) (gas constant)
T = 273 K (temperature)
Plugging these values into the ideal gas law equation, we can solve for V:
V = nRT / P
= (0.1 mol) * (0.0821 L·atm/(mol·K)) * (273 K) / (1 atm)
= 2.24 L
Therefore, the volume of hydrogen gas produced at STP is 2.24 L.
To calculate the volume of hydrogen gas (H2) produced at standard temperature and pressure (STP) when 6.54 g of zinc (Zn) reacts with excess dilute hydrochloric acid (HCl), you first need to determine the balanced chemical equation and understand the stoichiometry of the reaction.
From the given chemical equation: Zn + 2HCl -> ZnCl2 + H2
It shows that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.
Step 1: Convert the mass of zinc (Zn) to moles.
To do this, divide the given mass of zinc (65.4 g) by its molar mass (65.4 g/mol).
65.4 g Zn / 65.4 g/mol = 1 mol Zn
Step 2: Determine the moles of hydrogen gas (H2), based on the stoichiometry of the balanced equation.
From the balanced equation, we know that 1 mole of zinc (Zn) reacts to produce 1 mole of hydrogen gas (H2).
Therefore, 1 mol Zn will produce 1 mol H2.
Step 3: Calculate the volume of hydrogen gas (H2) at STP using the ideal gas law.
At STP, 1 mole of any gas occupies 22.4 liters.
So, the volume of hydrogen gas (H2) produced at STP can be calculated as follows:
1 mol H2 x 22.4 L/mol = 22.4 L
Therefore, when 6.54 g of zinc reacts with excess dilute hydrochloric acid, the volume of hydrogen gas produced at STP would be 22.4 liters.
The equation is
Zn(s) + 2HCl(aq) ==> ZnCl2(aq) + H2(g)
mols Zn = grams/atomic mass = ?
mols Zn = mols H2 (from the coefficients in the balanced equation)
L H2 = mols H2 x 22.4 L/mol = ?