The motion of an object can be described by the following formula, where u = initial velocity, v = final velocity, a = acceleration, and s = distance traveled.

Question

The motion of an object can be described by the following formula, where u = initial velocity, v = final velocity, a = acceleration, and s = distance traveled.

v2 = u2 + 2as

What is the equivalent equation solved for u, when u > 0?
A. u=/v^2+2as
B. u=(v^2-2as)
C. u=/v^2-as / 2
D. u=/v^2-2as

I think its
D. /v^2-2as
or A. /V^2+2as

Answer 1

u^2 = v^2 - 2as,

u = sqrt(v^2-2as).

Answer 2

To solve for u, we can rearrange the given equation:

v^2 = u^2 + 2as

Subtracting 2as from both sides:

v^2 - 2as = u^2

Taking the square root of both sides:

√(v^2 - 2as) = u

However, since u is specified to be greater than 0, we use the positive square root:

u = √(v^2 - 2as)

So, the correct answer is not D (/v^2-2as) because it lacks the square root operation. The correct answer is A (/v^2+2as), as it correctly represents the equation solved for u.