A 7.30 kg sign hangs from two wires. The first wire is attached to the left end,and pulls 28.0 N directly left. What is the X component of the force of the second wire
To find the x-component of the force of the second wire, we need to consider the forces acting on the sign in the x-direction.
From the information given, we know that one wire pulls the sign directly left with a force of 28.0 N. Since this force is directed to the left, it has a negative x-component.
Let's assume the x-component of the force exerted by the second wire is Fx. Since the sign is in equilibrium, the total x-component force acting on the sign should be zero.
So, we can write the equation:
Fx - 28.0 N = 0
Therefore, the x-component of the force of the second wire is equal in magnitude but opposite in direction to the force of the first wire, which is 28.0 N. So, the x-component of the force of the second wire is -28.0 N.