How do you balance:
C3H8 + O2 --> CO + H2O
nvm i got it;
2C3H8 + 7O2 -> 6CO + 8H2O
good work
To balance the chemical equation C3H8 + O2 -> CO + H2O, you need to make sure that the number of atoms of each element is equal on both sides of the equation.
Step 1: Count the atoms of each element on both sides of the equation.
On the left side:
C: 3 atoms
H: 8 atoms
O: 2 atoms
On the right side:
C: 1 atom
H: 2 atoms
O: 1 atom
Step 2: Balance carbon (C) atoms.
Multiply CO by 3 to match the number of carbon atoms on the left side. The equation becomes:
C3H8 + O2 -> 3CO + H2O
Step 3: Balance hydrogen (H) atoms.
Multiply H2O by 4 to match the number of hydrogen atoms on the left side. The equation becomes:
C3H8 + O2 -> 3CO + 4H2O
Step 4: Balance oxygen (O) atoms.
Count the total number of oxygen atoms on the right side:
3CO: 3 atoms
4H2O: 8 atoms
To balance the oxygen atoms, multiply O2 by 5. The equation becomes:
C3H8 + 5O2 -> 3CO + 4H2O
Now, let's check the atom counts on both sides:
On the left side:
C: 3 atoms
H: 8 atoms
O: 10 atoms
On the right side:
C: 3 atoms
H: 8 atoms
O: 10 atoms
The equation is now balanced, with an equal number of atoms on both sides:
C3H8 + 5O2 -> 3CO + 4H2O
To balance the chemical equation C3H8 + O2 → CO + H2O, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's the step-by-step process to balance this equation:
Step 1: Count the number of atoms for each element on both sides of the equation.
C: 3 on the left, 1 on the right
H: 8 on the left, 2 on the right
O: 2 on the left, 3 on the right
Step 2: Balance the carbon atoms (C).
Place a coefficient of 3 in front of CO on the right side:
C3H8 + O2 → 3CO + H2O
Step 3: Balance the hydrogen atoms (H).
Place a coefficient of 4 in front of H2O on the right side:
C3H8 + O2 → 3CO + 4H2O
Step 4: Balance the oxygen atoms (O).
Now, count the number of oxygen atoms again:
On the left: 2 O from O2 and 8 O from C3H8, totaling 10 O.
On the right: 6 O from 3CO and 4 O from 4H2O, totaling 10 O.
The equation is now balanced as:
C3H8 + O2 → 3CO + 4H2O
The balanced equation shows that 1 molecule of propane (C3H8) reacts with 5 molecules of oxygen gas (O2) to produce 3 molecules of carbon monoxide (CO) and 4 molecules of water (H2O).