Na₂SO₄(aq) + CaCl₂(aq) -> CaSO₄ (s) + 2NaCl(aq)
Now that we have a balanced chemical equation, let's write the ionic equation:
[?] + [?] -> [?] + [?]
A. Na₂SO₄ (aq)
B. 2Na₊(aq) + SO₂₋(aq)
C. Na₊(aq)+SO₂/₄₋(aq)
D. Na₂SO₄(s)
Please help! I have no clue about anything chemistry!!!
Na₂SO₄(aq) + CaCl₂(aq) -> CaSO₄ (s) + 2NaCl(aq)
If it's aq you know it will ionize (as I show it below) and if s(solid) it is shown as is.
2Na^+(aq) + SO4^2-(aq) + Ca^2+(aq) + 2Cl^-(aq) ==> CaSO4(s) + 2Na^+(aq) + 2Cl^-(aq)
No worries! I can help you.
To write the ionic equation, we need to identify the ions that are present in each compound in the balanced chemical equation.
The reactants are Na₂SO₄(aq) and CaCl₂(aq). Breaking down these compounds into their ions, we have:
Na₂SO₄(aq) consists of Na⁺ ions (sodium cations) and SO₄²⁻ ions (sulfate anions).
CaCl₂(aq) consists of Ca²⁺ ions (calcium cations) and 2Cl⁻ ions (chloride anions).
The products are CaSO₄(s) and 2NaCl(aq). Breaking down these compounds into their ions, we have:
CaSO₄(s) does not dissociate into ions since it is a solid.
2NaCl(aq) consists of 2Na⁺ ions (sodium cations) and 2Cl⁻ ions (chloride anions).
So, the ionic equation can be written as:
2Na⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> CaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
Therefore, the correct answer is [C] Na₊(aq) + SO₂/₄₋(aq).
To write the ionic equation, we need to understand the concept of ionic compounds and dissociation, as well as the charges on the ions involved.
In a balanced chemical equation, compounds that are in the aqueous (aq) state are typically dissociated into their respective ions when they are dissolved in water. This is known as dissociation or ionization.
Looking at the given equation, Na₂SO₄(aq) is an aqueous compound. Sodium sulfate (Na₂SO₄) dissociates into Na⁺ ions and SO₄²⁻ ions when dissolved in water.
So, we can write the dissociation of Na₂SO₄ as:
Na₂SO₄(aq) -> 2Na⁺(aq) + SO₄²⁻(aq)
Similarly, CaCl₂(aq) is also an aqueous compound. Calcium chloride (CaCl₂) dissociates into Ca²⁺ ions and 2Cl⁻ ions when dissolved in water.
So, we can write the dissociation of CaCl₂ as:
CaCl₂(aq) -> Ca²⁺(aq) + 2Cl⁻(aq)
Now, let's substitute the dissociated ions into the balanced chemical equation:
2Na⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> CaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
From the above equation, we can see that the ionic equation is:
2Na⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2Cl⁻(aq) -> CaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
So, the correct answer is:
B. 2Na⁺(aq) + SO₄²⁻(aq) -> CaSO₄(s) + 2Cl⁻(aq)