100g of sulfuric acid is added to 100g of zinc. Find the mass of the ionic substance formed.
Zn + H2SO4(aq)>>ZnSO4 (aq) + H2
The problemhere is stating 100g of sulfuric acid, and sulfuric acid is not 100percent H2SO4. So I am wondering what was the concentration of sulfuric acid, because 100 g of sulfuric acid is not 100 g of H2SO4 alone.
for bobpursley : it said mass not word equation
To find the mass of the ionic substance formed when sulfuric acid reacts with zinc, we need to determine the balanced equation for the reaction and then look at the molar ratios.
The balanced equation for the reaction between sulfuric acid (H2SO4) and zinc (Zn) can be written as:
H2SO4 + Zn -> ZnSO4 + H2
From the balanced equation, we can see that 1 mole of sulfuric acid reacts with 1 mole of zinc to produce 1 mole of zinc sulfate.
To solve this problem, we need to convert the given masses of sulfuric acid and zinc to moles using their respective molar masses.
The molar mass of sulfuric acid (H2SO4) is:
(2 atoms of hydrogen (H) × 1.008 g/mol) + (1 atom of sulfur (S) × 32.06 g/mol) + (4 atoms of oxygen (O) × 16.00 g/mol) = 98.09 g/mol
The molar mass of zinc (Zn) is:
1 atom of zinc (Zn) × 65.38 g/mol = 65.38 g/mol
Now, let's calculate the number of moles of sulfuric acid and zinc:
Moles of sulfuric acid = mass of sulfuric acid / molar mass of sulfuric acid = 100 g / 98.09 g/mol ≈ 1.02 mol
Moles of zinc = mass of zinc / molar mass of zinc = 100 g / 65.38 g/mol ≈ 1.53 mol
Since the reaction is 1:1 between sulfuric acid and zinc, we can see that 1.02 moles of sulfuric acid (H2SO4) will react with 1.02 moles of zinc (Zn).
However, since we have an excess of 1.53 moles of zinc, only 1.02 moles of zinc will react completely. Therefore, the number of moles of zinc that will actually react is limited by the amount of sulfuric acid available.
Now, we can use the balanced equation to determine the molar ratio between zinc sulfate (ZnSO4) and zinc (Zn). From the equation, we see that the ratio is 1:1.
Therefore, the mass of the ionic substance formed, which is zinc sulfate (ZnSO4), will be equal to the molar mass of zinc sulfate multiplied by the number of moles of zinc that reacted.
The molar mass of zinc sulfate (ZnSO4) is:
1 atom of zinc (Zn) × 65.38 g/mol + 1 atom of sulfur (S) × 32.06 g/mol + 4 atoms of oxygen (O) × 16.00 g/mol = 161.38 g/mol
Mass of ionic substance formed = molar mass of zinc sulfate × moles of zinc = 161.38 g/mol × 1.02 mol ≈ 164.60 g
Therefore, the mass of the ionic substance formed (zinc sulfate) is approximately 164.60 grams.