-14x^3
————
X^3-5x^4
I know the answer is
1-5x
——
-14x
But does
x ≠ 1/5,0
x ≠ 0
x ≠ 1/5
I think x ≠ 1/5, 0, but I’m not sure. Thanks!!!!!
I would interpret your
-14x^3
————
X^3-5x^4
as -14x^3/(x^3 - 5x^4)
= -14x^3/(x^3(1 - 5x))
= -14/(1-5x), where x ≠ 0, technically x ≠ 1/5 is implicit and thus does not have to be stated.
btw, your answer of (1-5x)/-14x is not correct.
I see. The answer would be
-14x
——— where x ≠ 1/5, 0
1-5x
Right?... :-) This makes a lot of sense now. Got my answer mixed up. Thanks!
It is not -14x on top, it is -14
we cancelled the x^3
Oops. I just can’t seem to get it right. Thanks! :-P
To determine the values of x for which the expression is undefined, we need to find the values that make the denominator equal to zero. In this case, the denominator is x^3 - 5x^4.
Setting the denominator equal to zero:
x^3 - 5x^4 = 0
Factoring out x^3, we get:
x^3(1 - 5x) = 0
Now, we have two factors: x^3 = 0 and (1 - 5x) = 0.
For x^3 = 0, the only solution is x = 0. So, x = 0 is a value that makes the expression undefined.
For (1 - 5x) = 0, we solve for x:
1 - 5x = 0
5x = 1
x = 1/5
So, x = 1/5 is another value that makes the expression undefined.
To summarize, the values for which the expression is undefined are x = 0 and x = 1/5.
Therefore, your initial thoughts were correct:
x ≠ 0 and x ≠ 1/5.