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How many moles of water vapour are formed when 10L of butane gas C4H10is burned in oxygen at STP

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Shakiri

  1. 2C4H10 + 13O2 ==> 8CO2 + 10H2O
    10 L C4H10 @ STP will produce 10L x 10/2 = 50 L H2O @ STP.
    1 mol H2O will occupy 22.4 L. So how many mols are in 50 L?
    Post your work if you get stuck.

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    DrBob222

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