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How many moles of water vapour are formed when 10L of butane gas C4H10is burned in oxygen at STP

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Shakiri

  1. 2C4H10 + 13O2 ==> 8CO2 + 10H2O
    10 L C4H10 @ STP will produce 10L x 10/2 = 50 L H2O @ STP.
    1 mol H2O will occupy 22.4 L. So how many mols are in 50 L?
    Post your work if you get stuck.

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    DrBob222

  2. 2c4h10+13o2

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    Nuhamin

  4. Thank you I am very happy to get this answer

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    Muradi

  5. 1mole of any gas equals the volume 22.4l. so 1mole=22.4l x =50l use chirs cross method and x=2.2mol

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    mintesinot

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