How many moles of water are produced when 0.48 moles of butane c4h10 react?
write the balanced equation
It will give you the ratio of moles used and produced.
To determine how many moles of water are produced when 0.48 moles of butane (C4H10) react, we need to balance the chemical equation first.
The balanced equation for the combustion of butane is as follows:
2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O
From the balanced equation, we can see that for every 2 moles of butane, 10 moles of water are produced.
Therefore, to find the number of moles of water produced when 0.48 moles of butane react, we can set up a proportion:
2 moles of butane / 10 moles of water = 0.48 moles of butane / X moles of water
Cross-multiplying and solving for X (the number of moles of water):
2 * X = 0.48 * 10
X = (0.48 * 10) / 2
X = 4.8 / 2
X = 2.4 moles
Therefore, 0.48 moles of butane will produce 2.4 moles of water.
To determine the number of moles of water produced when a certain amount of butane (C4H10) reacts, we first need to know the balanced chemical equation for the reaction. Assuming the combustion of butane, the balanced equation is:
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
From this equation, we see that every 2 moles of butane reacts to produce 10 moles of water. This means that there is a 5:1 ratio between butane and water.
Now, we can calculate the number of moles of water produced when 0.48 moles of butane react.
0.48 moles of butane * (10 moles of water / 2 moles of butane) = 2.4 moles of water
Therefore, when 0.48 moles of butane reacts, it produces 2.4 moles of water.