the basicity of tetraoxosulphate 6 acid is 2 explain the statement with an equation and show the reaction between tetraoxosulphate 6 acid with potassium hydroxide
Firstly a base is a substance which will neutralize an acid to yield salt and water only.Tetraoxosulphate(vi) acid in an equation is H2SO4
Very interesting
You guys don't answer questions well
To explain the statement that the basicity of tetraoxosulphate 6 acid is 2, we need to understand the concept of basicity and look at the chemical formula of tetraoxosulphate 6 acid, also known as sulfuric acid (H2SO4).
Basicity refers to the number of replaceable hydrogen ions (protons) present in an acid molecule. In the case of sulfuric acid (H2SO4), there are two replaceable hydrogen ions. Each hydrogen ion can react with a base to form a salt and water.
The equation for the ionization of sulfuric acid in water is as follows:
H2SO4 + H2O -> H3O+ + HSO4-
In this equation, one hydrogen ion (H+) is released, forming hydronium ion (H3O+). The remaining portion of the molecule, the bisulphate ion (HSO4-), is now negatively charged.
When sulfuric acid reacts with a base like potassium hydroxide (KOH), the hydrogen ion (H+) from the acid combines with the hydroxide ion (OH-) from the base to form water (H2O), while the remaining ions combine to form a salt. Here's the equation for the reaction between sulfuric acid and potassium hydroxide:
H2SO4 + 2KOH -> K2SO4 + 2H2O
In this reaction, two molecules of potassium hydroxide (KOH) react with one molecule of sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4) and two molecules of water (H2O).
So, the basicity of tetraoxosulphate 6 acid (sulfuric acid) is 2 because it has two replaceable hydrogen ions that can react with bases.