If 40ml of 1.60M HCl and 60 ml of 2M NaOH is mixed calculate the concentration of Na+, Cl-,OH,- ions
Na: 2M(60/100)
Cl: 2M (60/100)
OH: (1.6*.04+2*0.6)/.100
I think (OH^-) should be as follows:.
.......................HCl + NaOH ==> NaCl + H2O
I mmols...64.......120............0...........0
C....................-64........-64..........+64........+64
E.......................0..........56............64........64
So the (OH^-) comes from what's left of the OH from the NaOH. That ignores any OH from the H2O for Kw.
Then (OH^-) = millimoles/mL = 56/100 = 0.56 M.
And (Cl^-) should be (1.6*40/100 = 0.64
To calculate the concentration of Na+, Cl-, and OH- ions in the mixture, we need to first determine the number of moles of each ion in the solution.
Let's start with HCl.
Given:
Volume of HCl solution = 40 mL
Concentration of HCl = 1.60 M
To determine the number of moles of HCl, we can use the equation:
moles = concentration x volume
moles of HCl = 1.60 M x 0.040 L = 0.064 moles
Since HCl is a strong acid, it will completely dissociate in water, resulting in an equal number of H+ and Cl- ions. Therefore, the number of moles of Cl- ions is also 0.064 moles.
Next, let's move on to NaOH.
Given:
Volume of NaOH solution = 60 mL
Concentration of NaOH = 2 M
Using the same equation as before, we can calculate the number of moles of NaOH:
moles of NaOH = 2 M x 0.060 L = 0.12 moles
NaOH is a strong base, so it will dissociate into an equal number of Na+ and OH- ions. Therefore, the number of moles of Na+ ions is also 0.12 moles, and the number of moles of OH- ions is also 0.12 moles.
Finally, let's calculate the concentrations of each ion.
Concentration of Na+ ions = moles of Na+ ions / total volume of solution
= 0.12 moles / (40 mL + 60 mL)
= 0.12 moles / 0.1 L
= 1.2 M
Concentration of Cl- ions = moles of Cl- ions / total volume of solution
= 0.064 moles / 0.1 L
= 0.64 M
Concentration of OH- ions = moles of OH- ions / total volume of solution
= 0.12 moles / 0.1 L
= 1.2 M
Therefore, the concentration of Na+ ions is 1.2 M, the concentration of Cl- ions is 0.64 M, and the concentration of OH- ions is 1.2 M in the mixture.