A car of mass 1200kg is moving with a velocity of 25ms-1 around a flat bend of radius 150m. Determine the minimum frictional force between the tyres and the road thatwill prevent the car from sliding off
centripetal force= friction force
m v^2/r= mu*mg=minimal friction force.
answer: m v^2/r
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To determine the minimum frictional force between the tires and the road that will prevent the car from sliding off, we need to consider the forces acting on the car.
First, we need to calculate the centripetal force required to keep the car moving in a circular path. This force is provided by the friction between the tires and the road.
The centripetal force is given by the equation:
F = (mv^2) / r
where F is the centripetal force, m is the mass of the car, v is the velocity, and r is the radius of the bend.
Using the given values:
m = 1200 kg
v = 25 m/s
r = 150 m
Plugging these values into the equation, we get:
F = (1200 kg * (25 m/s)^2) / 150 m
Calculating the centripetal force:
F = 50000 N
Therefore, the minimum frictional force required between the tires and the road to prevent the car from sliding off is 50000 N.