physics

four forces 8N 6n 2n and 4n act on a point O in the directionsnorth east south and west respectively find the magnitude of their result and the direction of their resultant force

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asked by Jo
  1. forces in opposite directions subtract from each other

    so the "effective forces here are ... 6N north and 2N east

    magnitude ... √(6^2 + 2^2)

    direction ... [arctan(2 / 6)] east of north

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    posted by R_scott
  2. Force total=8N + 6E + 2S +4W= N (8-2) + E(6-4)= you finish
    magnitude = sqrt (6^2+2^2)
    direction= arctan E/N=arctan 2/6 E of N

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