16. A positive and a negative charge, each with a magnitude of 3.65 x 10-4 C, are separated by a distance of 0.67 m. Find the
force on each of the particles. You must show your work for credit.
it is supposed to be 10^-4
The force on each is the same, but directed towards the other:
Force=k q1*q2/d^2=8.98e9*(3.65e-4)^2 / .67^2
not 10^-4
is it 4.9x10^6 that is what i got
To find the force on each particle, we need to use Coulomb's law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
The equation for the force between two charges is:
F = (k * q1 * q2) / r^2
Where:
F is the force between the charges,
k is the Coulomb's constant (k = 9 x 10^9 N m^2/C^2),
q1 and q2 are the magnitudes of the charges, and
r is the distance between the charges.
In this case, both charges have a magnitude of 3.65 x 10^-4 C, and the distance between them is 0.67 m.
Plugging in the values into the formula:
F = (9 x 10^9 N m^2/C^2) * (3.65 x 10^-4 C) * (3.65 x 10^-4 C) / (0.67 m)^2
F = (9 x 10^9 N m^2/C^2) * (3.65 x 10^-4 C)^2 / (0.67 m)^2
Simplifying the calculation:
F = (9 x 10^9 N m^2/C^2) * (3.65 x 10^-4 C)^2 / (0.67 m)^2
F = 9 x 10^9 N m^2/C^2 * 13.3225 x 10^-8 C^2 / 0.4489 m^2
F = 1.19592 x 10^3 N
Therefore, the force on each particle is approximately 1.19592 x 10^3 N.