How do I solve logarithms, I am completely lost and need help, if there's any way someone could reach out to me to tutor me shortly I would appreciate it, that or write a simple yet in depth review of how to do it. I don't get the "math terms"

An excellent introduction to logarithms is done by Sal Khan, the internet's favourite educator, in this video. Give it a try, he does a great job.

www.khanacademy.org/math/algebra2/exponential-and-logarithmic-functions/introduction-to-logarithms/v/logarithms

bookmark this website, you will love it

I second that website.

https://www.khanacademy.org/math/algebra2/exponential-and-logarithmic-functions/introduction-to-logarithms/a/intro-to-logarithms

I'm sorry to hear that you're feeling lost with logarithms! Don't worry, I'm here to help explain how to solve them. While I can't provide real-time tutoring, I can definitely give you a simple yet in-depth review of logarithms that will hopefully clarify things for you.

First, let's start with the definition of a logarithm. A logarithm is the inverse operation of exponentiation. It helps us solve equations where the variable is in an exponent.

The basic form of a logarithm is written as: log(base b) (x) = y. Here, "b" is the base of the logarithm, "x" is the argument or value for which you're calculating the logarithm, and "y" is the result or solution.

To solve logarithms, you'll need to understand the properties and rules associated with them. Here are the three main properties:

1. Product Rule: log(base b) (xy) = log(base b) (x) + log(base b) (y)
This property allows you to split the logarithm of a product into the sum of the logarithms of the individual factors.

2. Quotient Rule: log(base b) (x/y) = log(base b) (x) - log(base b) (y)
This property lets you break down the logarithm of a quotient into the difference of the logarithms of the numerator and denominator.

3. Power Rule: log(base b) (x^a) = a * log(base b) (x)
This rule lets you bring the exponent "a" down as a coefficient in front of the logarithm.

Now, let's go through an example to see these concepts in action.

Example: Solve the logarithm equation log(base 2) (8) = x.

To solve this, we need to convert the logarithmic equation into an exponential one. The general form is: b^y = x, where b is the base, y is the exponent, and x is the result.

Using this equation, we can rewrite the log equation as 2^x = 8. Now, we need to find the value of x that satisfies this exponential equation.

We know that 2^3 = 8, so x = 3 is the solution to our logarithm equation.

Remember to practice solving more examples using the properties and rules mentioned above to become more comfortable with logarithms. Additionally, you can find various online resources, video tutorials, or textbooks specifically dedicated to logarithms that can help deepen your understanding.

I hope this explanation helps you grasp the concept of logarithms! If you have any further questions, feel free to ask.