A 65 kg student consumes 2500 Cal each day and stays at the same weight. For three days in a row, while visiting his parents, she eats 3500 Cal and, wanting to keep from gaining weight decides to "work off" the excess by jumping up and down.

Question

A 65 kg student consumes 2500 Cal each day and stays at the same weight. For three days in a row, while visiting his parents, she eats 3500 Cal and, wanting to keep from gaining weight decides to "work off" the excess by jumping up and down.

With each jump, he accelerates to a speed of 3.2 m/s before leaving the ground.

b) How many jumps must he do to keep his weight? (body efficiency= 25%)

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Which formula did u use to obtain this?
jumps=(2500C*.25*1000c/C*4.18J/c )/(1/2*65*3.2^2)

Answer 1

total energy= energyonEachJump*number Jumps

number jumps= total energy/energy of each