A body of mass 10kg is acted on by a constant force of 20n for 3second. Calculate the kinetic energy at the end of the time.
Honestly, it depends on the initial velocity.
force*time=mass*changeinvelocity
changeinvelocity=force*time/mass
Now if the initial velocity is zero, then, and only then, the final velocity is =change invelocity, and one would have
vfinal=force*time/mass
and vfinal ^2=(20*3/10)^2=36
final KE= 1/2 m vfinal^2=1/2 (10*36)= I get about 180m/s
A body of mass 10kg is acted on by a constant force if 20N for 3seconds .calculate the kinetic energy .the distance traveled
A BODY OF MASS
To determine the kinetic energy of the body at the end of the given time, we can use the equation:
Kinetic Energy = 1/2 * mass * velocity^2
First, let's find the acceleration of the body using Newton's second law of motion:
Force = mass * acceleration
Rearranging the equation, we have:
acceleration = Force / mass
Substituting the given values:
acceleration = 20N / 10kg = 2 m/s^2
Next, we can calculate the final velocity of the body using the equation of motion:
velocity = initial velocity + (acceleration * time)
Since the initial velocity is not given, we assume it is 0 m/s (at rest):
velocity = 0 + (2 m/s^2 * 3s) = 6 m/s
Now, let's substitute the mass (10 kg) and the final velocity (6 m/s) into the kinetic energy equation:
Kinetic Energy = 1/2 * mass * velocity^2
= 1/2 * 10kg * (6 m/s)^2
= 1/2 * 10kg * 36 m^2/s^2
= 180 Joules
Therefore, the kinetic energy of the body at the end of 3 seconds is 180 Joules.