What happens when an atom gives up loosely held valence electrons to another atom?
A. The two atoms form a mixture.
B. A chemical bond forms between the two atoms.
C. A chemical compound splits into separate elements.
D. The two atoms combine to create an element.
So, a b c or d?
if not then tell me what it is
The correct answer is B. A chemical bond forms between the two atoms.
When an atom gives up loosely held valence electrons to another atom, it is participating in a process called chemical bonding. Chemical bonding occurs when atoms interact with each other to form stable compounds. In this case, the atom that gives up valence electrons becomes a positively charged ion (cation), while the atom that accepts the electrons becomes a negatively charged ion (anion).
The process of giving up electrons is known as "electron donation" or "oxidation," while the process of accepting electrons is referred to as "electron acceptance" or "reduction." These two processes together form an ionic bond, which is a strong attractive force between the oppositely charged ions.
This type of bonding typically occurs between metals and nonmetals. The metal atoms tend to lose electrons and become positive ions, while the nonmetal atoms tend to gain electrons and become negative ions. The resulting ionic compound is held together by the electrostatic attraction between these oppositely charged ions.
Therefore, option B is the correct answer as a chemical bond forms when an atom gives up loosely held valence electrons to another atom.