When 2 moles of K3PO4 is dissolved in water, how many moles of ions are produced? For your answer do not put units, just the numeric value.
So you will have 6 mols of K^+ plus 2 mols (PO4)^3-
When 2 moles of K3PO4 is dissolved in water, it dissociates into 2 moles of K+ ions and 1 mole of PO4^3- ions. Therefore, a total of 3 moles of ions are produced.
To find the number of moles of ions produced when 2 moles of K3PO4 is dissolved in water, we need to determine the dissociation of K3PO4 in water.
K3PO4 is a compound composed of three potassium ions (K+) and one phosphate ion (PO4^3-). When it dissolves in water, it dissociates into its respective ions.
The dissociation equation is:
K3PO4 → 3K+ + PO4^3-
According to the equation, for every 1 mole of K3PO4 dissolved, it produces 3 moles of K+ ions and 1 mole of PO4^3- ions.
Since you have given that we have 2 moles of K3PO4, we can calculate the number of moles of ions produced:
3 moles K+ ions/mole K3PO4 × 2 moles K3PO4 = 6 moles K+ ions
1 mole PO4^3- ions/mole K3PO4 × 2 moles K3PO4 = 2 moles PO4^3- ions
Therefore, when 2 moles of K3PO4 is dissolved in water, it produces 6 moles of K+ ions and 2 moles of PO4^3- ions.