In the outer space, a constant force is applied to a 32.5 kg probe initially at rest. The probe moves a distance of 100 m in 10 s. Could some one show me the step to step on how to find
(a) What acceleration does this force produce?
(b) What is the magnitude of the force?
average velocity= 100/10 = 10 m/s
but average velocity= (vf+vo)/2=vf/2 so vf=20m/s
vf^2=vo^2+2ad
20^2=2*a*100
solve for a.
force= mass*a
a. V = d/t = 100m/10s = 10 m/s.
V = Vo + a*t = 10.
0 + a*10 = 10,
a = 1 m/s^2.
F = M*a
To find the answers to these questions, we can use Newton's second law of motion, which states that the force applied to an object equals the mass of the object multiplied by its acceleration.
(a) To find the acceleration, we can use the formula:
acceleration = (change in velocity) / time
Since the probe starts from rest, its initial velocity is 0 m/s. The final velocity can be found using the formula:
final velocity = (displacement) / time
Substituting the given values:
final velocity = 100 m / 10 s = 10 m/s
Now, we can find the change in velocity:
change in velocity = final velocity - initial velocity
= 10 m/s - 0 m/s
= 10 m/s
Finally, we can calculate the acceleration:
acceleration = change in velocity / time
= 10 m/s / 10 s
= 1 m/s^2
Therefore, the acceleration produced by the force is 1 m/s^2.
(b) To find the magnitude of the force, we can use Newton's second law:
force = mass * acceleration
Substituting the given values:
force = 32.5 kg * 1 m/s^2
= 32.5 N
Therefore, the magnitude of the force is 32.5 Newtons.