compare from greatest to least the accelerations of these skydivers
a)1000-N man with 800N of air drag
b) 800-N woman with 700N OF air drag
C)700-N woman with 600N of air drag
d) 100-N dog with 90 N of air drag
Greatest -------- -------- ---------- --------Least
To compare the accelerations of these skydivers, we need to calculate their net forces and use Newton's second law of motion: F = ma. The acceleration can be determined by dividing the net force by the mass of the skydiver. However, since the mass is not provided, we can't directly compare the accelerations based on the given information.
To compare the accelerations of the skydivers, we need to calculate the net force acting on each skydiver using Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
The formula for calculating net force is:
Net Force = Applied Force - Air Drag
Let's calculate the net force and compare the accelerations:
a) 1000-N man with 800N of air drag:
Net Force = 1000N - 800N = 200N
b) 800-N woman with 700N of air drag:
Net Force = 800N - 700N = 100N
c) 700-N woman with 600N of air drag:
Net Force = 700N - 600N = 100N
d) 100-N dog with 90N of air drag:
Net Force = 100N - 90N = 10N
Now, let's compare the net forces and arrange them from greatest to least:
a) 200N
b) 100N
c) 100N
d) 10N
Therefore, the arrangements of the skydivers from greatest to least acceleration are:
a) 1000-N man with 800N of air drag
b) 800-N woman with 700N of air drag
c) 700-N woman with 600N of air drag
d) 100-N dog with 90 N of air drag
acceleration= (pushing force-friction)(9.8)/weightgiven
a) a= 200*9.8/1000=9.8/5
b) a= 100*9.8/800=9.8/8
you do the rest, then rank them.