4. In a shopping mall, two elevators pass each other moving in opposite directions. Each elevator to the other is 10 m/s. What is the velocity of each elevator relative to a person standing on the ground?

One elevator has a velocity of 5 m/s and the other elevator has a velocity of -5 m/s.
Both elevators have a velocity of 5 m/s.
Both elevators have a velocity of 10 m/s.
One elevator has a velocity of 10 m/s, and the other elevator has a velocity of -10 m/s.

I’m really confused on this one. Any help? If so can you explain how to get the answer and the correct answer or at least walk me through the problem and show me how to get the correct answer?

To answer this question, we need to understand the concept of relative velocity. The velocity of an object is its speed in a given direction. Relative velocity refers to the velocity of one object with respect to another object.

In this case, we have two elevators passing each other in opposite directions. The velocity of one elevator with respect to the other is given as 10 m/s. Now we need to determine the velocity of each elevator relative to a person standing on the ground.

To find the relative velocity, we can simply subtract the velocity of one elevator from the velocity of the other elevator. In this case, one elevator has a velocity of 5 m/s, and the other elevator has a velocity of -5 m/s.

So, to find the velocity of each elevator relative to a person standing on the ground, you subtract the velocity of one elevator from the other.

For the first elevator (with a velocity of 5 m/s), the relative velocity is 5 m/s - (-5 m/s) = 10 m/s.

For the second elevator (with a velocity of -5 m/s), the relative velocity is -5 m/s - 5 m/s = -10 m/s.

Therefore, the correct answer is: One elevator has a velocity of 10 m/s, and the other elevator has a velocity of -10 m/s, relative to a person standing on the ground.

Hey one is going up and the other down

so one v is +
and the other v is - relative to ground
+5 - (-5) = 5+5 = 10
or equivalently
-5 - (+5) = -10
depending on which you look from :)