Log power of(3n-1) to base 10-Log power 2 to base 10 =3
we have discussed this before. It makes no sense. What is being taken to the power? log (x^(3n-1)) ? If you want to get help, you will just have to write in standard notation. As it is, the wording makes no sense. The base 10=3 makes no sense.
I have a sneaky suspicion that Ghazali means:
log 10 (3n-1) - log 10 2 = 3
of course, if the base is 10 , the base is understood and
we don't even have to write it,
so is it
log (3n-1) - log 2 = 3 ???, if so then
log ( (3n-1)/2) = 3
(3n-1)/2 = 10^3 = 1000
3n - 1 = 2000
3n = 2001
n = 667
To solve the equation: Log power of (3n-1) to base 10 - Log power 2 to base 10 = 3, we will apply the properties of logarithms.
First, let's simplify the equation:
Log10(3n-1) - Log10(2) = 3
Using the property of logarithms, we can rewrite the equation as:
Log10((3n-1)/2) = 3
Now, let's eliminate the logarithm. In order to do this, we need to rewrite the equation in exponential form:
10^3 = (3n-1)/2
Simplifying further:
1000 = (3n-1)/2
Multiplying both sides of the equation by 2:
2000 = 3n - 1
Now, let's isolate the variable n. Adding 1 to both sides:
2001 = 3n
Dividing both sides by 3:
n = 2001/3
Thus, the value of n is 667.