There are 3.01X1023 atoms of gold, 1 mole of platinum, 3.01 moles of silver. Which one contains more atoms
each mole contains 6.023e23 atoms, so you are comparing 1/2; 1; 3 I would bet on the Ag
To determine which substance contains more atoms, we need to compare the number of atoms in each substance.
1 mole of any substance contains Avogadro's number of atoms, which is approximately 6.022 × 10^23 atoms.
Given:
- 3.01 × 10^23 atoms of gold
- 1 mole of platinum
- 3.01 moles of silver
We know that the gold sample contains exactly 3.01 × 10^23 atoms.
For the platinum sample, 1 mole of platinum contains approximately 6.022 × 10^23 atoms. Therefore, it also has 6.022 × 10^23 atoms.
For the silver sample, 1 mole of silver contains approximately 6.022 × 10^23 atoms. As we have 3.01 moles of silver, we can calculate the total number of atoms using the formula:
Total Number of Atoms = Number of Moles × Avogadro's Number
Total Number of Atoms = 3.01 moles × 6.022 × 10^23 atoms/mole
Calculating the total number of atoms of silver:
Total Number of Atoms = (3.01) × (6.022 × 10^23)
Total Number of Atoms = 1.81222 × 10^24 atoms
Comparing the number of atoms:
The number of atoms in each substance is as follows:
- Gold: 3.01 × 10^23 atoms
- Platinum: 6.022 × 10^23 atoms
- Silver: 1.81222 × 10^24 atoms
So, the substance that contains the most atoms is silver with 1.81222 × 10^24 atoms.