An orange of mass 40g falls freely from the tree to the ground through a distance of 2.5m. Calculate the potential energy of the orange before it hits the ground. g=10m/s²
g is not 10m/s^2 anywhere on Earth.
Frankly, I like to call g not the acceleration due to gravity, but the Gravity Field
Gravity Field= 9.8Newtons/kilogram or 9.8N/kg
PE=massinKg*GravityField*height=.04kg*9.8N/kg*2.5m=...
remember that a N-m is a joule, by definition.
Solve the question
To calculate the potential energy of the orange before it hits the ground, we can use the formula:
Potential Energy = Mass x Gravity x Height
Given:
Mass (m) = 40g = 0.04kg
Height (h) = 2.5m
Gravity (g) = 10m/s²
Plugging the values into the formula, we get:
Potential Energy = 0.04kg x 10m/s² x 2.5m
= 1 Joule
Therefore, the potential energy of the orange before it hits the ground is 1 Joule.
To calculate the potential energy of the orange, we need to use the formula:
Potential Energy = mass * gravity * height
Given:
Mass of the orange (m) = 40g = 0.04 kg
Gravity (g) = 10 m/s²
Height (h) = 2.5m
First, we convert the mass from grams to kilograms by dividing it by 1000:
Mass (m) = 0.04 kg
Next, we can substitute the values into the formula:
Potential Energy = 0.04 kg * 10 m/s² * 2.5 m
Multiply the values together:
Potential Energy = 0.04 kg * 10 m/s² * 2.5 m = 1 J (Joule)
Therefore, the potential energy of the orange before it hits the ground is 1 Joule.