Getting my head twisted around by the wording of these two questions, any help would be appreciated. My answers/ideas are below each question.

1) Briefly explain whether there would there be more or fewer configurations available for the gas if the particles were distinguishable, than in the case of bosons where the particles are indistinguishable.

My Answer: There would be more configurations as you can have more than one variation of the same configuration if the particles are known. i.e A,B,C,D and D,C,B,A. This is not possible with indistinguishable particles.


2) Also explain whether the probability of finding two or more particles in the same state would be higher or lower than in the case of bosons. What does this imply about the sociability of bosons?

My Answer: I am unsure, would it not be higher simply because we have more configurations to 'choose' from?


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  1. If the particles are distinguishable, then the Pr(states) would be lower, for the reason you stated.

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